I'm sure others have done it; however, this is commonly known as the Voodoo Labs bypass. It's an interesting way of bypassing a pedal using a DPDT switch while including an LED indicator.
Before 3PDT switches became available, designers had to choose between not true bypass with a LED or true-bypass without an LED (until the millennium bypass appeared, but that's another story).
Here's how it works:
PEDAL ON
The LED in the photo FET turns on, and the resistance of the FET drops down to a few hundred ohms - signal flows into the effect circuit, and the effect circuit output is routed to the output jack.
PEDAL OFF
The LED in the photo FET is off - the resistance of the FET increases to a few hundred megohms, blocking the signal from reaching the circuit. The FET is also grounded. So the signal sees a very large resistor to ground instead of a circuit. The signal from the input jack is routed to the output jack.
Or an even better explanation by R.G. Keen can be found here
do you think a h11a1 would work? thanks!
ReplyDeleteI'm guessing no - FET vs Transistor. But I've never tried it, so maybe...
Deletethere's a report that it works with SI Transistor, too. https://forum.pedalpcb.com/threads/voodoolabs-optical-bypass.11329/
DeleteInteresting, thanks for the link
DeleteI once built on h11f1 and this switching worked, but I kept feeling that the bypass off_fx level became lower than the bypass level of the passive effect loop signal.
Delete